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Mathematics, 01.09.2019 16:20 Zaida21

Could you me?
the work of a student to solve the equation
2(5y βˆ’ 2) = 12 + 6y is shown below:
step 1: 2(5y βˆ’ 2) = 12 + 6y
step 2: 7y βˆ’ 4 = 12 + 6y
step 3: y βˆ’ 4 = 10
step 4: y = 14
step 5: y = 7
in which step did the student first make an error and what is the correct step? step 2: 7y βˆ’ 4 = 6 + 3y
step 2: 10y βˆ’ 4 = 12 + 6y
step 3: 5y βˆ’ 2 = 2(10 + 3y)
step 3: 2(5y βˆ’ 2) = 10 + 3y

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Answers: 2

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Could you me?
the work of a student to solve the equation
2(5y βˆ’ 2) = 12 + 6y is sho...
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