How do i write a rule for the nth term of the sequence?

first of all we have the 5th term and 2nd term

T5=768 =a*r^4

T2=-12=a*r ^1

make a subject of formula in the both equations

that is a=T2/r and T5/r^4

a=12/r and a=768/r^4

when u equate them u will get

-64=r^3 so r=-4 then to find a that is 1st term

since second term is T2=a*r=12 an r=-4 then

a=12/-4 hence a=-3

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

i think is g(1)=-1.

hope that i can