He function y=−16x2+v0x models the height of a golf ball in feet x seconds after a player hits it. in the equation of the function, v0 is the initial velocity of the ball in feet per second. the ball returns to the ground 3 seconds after it is hit.

what is the value of v0 ?

enter your answer in the box

V0 = 48 feet per second is the answer.

Step-by-step explanation:

The given function which represents height of a golf ball in feet after x seconds after a player hits it.

y = -16x² + v0x

here v0 is the initial velocity and we have to calculate initial velocity. The ball returns to the ground 3 seconds after it is hit.

After 3 seconds height of the ball will be 0.

Now from the given function

0 = -16(3)² + v0×3

3v = 16×9

v0 = 16×9/3 = 48 feet per second.

answer: it is 1: 47 pm