Circle o has center (2, 6) and passes through the point p (4, 3). write the equation of the line that is tangent to circle o at point p
a: y=3/2,x-3
b: y=2/3,x+1/3
c: y=-3/2,x+9
d: y=-2/3x+17/3

First, fine the slope of the lines.

m=3-6/4-2
m=-3/2

To find the perpendicular slope of this, find the opposite reciprocal, or 2/3

Use formula y=mx+b to find the equation of this line.

3=(2/3)(4)+b
3=b+8/3
3-8/3=b+8/3-8/3
1/3=b

Now, plug in the values

y=2/3x+1/3, or B