The diagonals of rhombus abcd intersect at point
e. the area of abcd is 168 .if ed = 8 inches, find ac.

ac= 21

Step-by-step explanation:

Rhombus is a parallelogram in which diagonals bisect each other .

Given: Area of rhombus is 168 .

The diagonals of rhombus abcd intersect at point e. It's diagonals are ac and bd . We know that diagonals of rhombus bisect each other ,so, bd=2de . So, .

Also, area of rhombus is where are the diagonals of rhombus .

As area of rhombus is 168 , we get ,

Let

So, we get ,

Therefore,

i'm sorry i don't know

step-by-step explanation: