Question 1:
y=5^4x-3 what is the ordered pair? (its 5 to the power of 4)
question 2:
which ordered pair makes the equation true?
2y=-5x-4
a. (-2,3)
b. (1,-4)
c. (0,2)
d. (-1,1)

Question 1:
I'm actually not sure which term you ment exactly, so I calculated the solution for three possible variations of your term, depending on how one sets the brackets.

To calculate an ordered pay just set x or y to some value, insert it into the equation and you get the solution for the other variable.
In these calculations I always picked x so values would get eliminated or as close to 0 as possible to make it easier.

variation 1 of term:
y=(5^4)*(x-3)
insert x=3
y=(5^4)*(3-3)==(5^4)*0=0
pair: (3,0)

variation 2 of term:
y=(5^4)*x-3
insert x=0:
y=(5^4)*0-3=0-3=-3
pair: (0,-3)

variation 3 of term:
y=5^(4*x-3)
insert x=1:
y=5^(4*1-3)=5^1=5
pair: (1,5)

question 2:
2y=-5x-4
just insert the pairs as (x,y) into the equation:

a. (-2,3)
2*3=-5*-2-4
6=10-4 yes

b. (1,-4)
2*-4=-5*1-4
-8=-9 no

c. (0,2)
2*2=-5*0-4
4=-4 no

d. (-1,1)
2*1=-5*-1-4
2=5-4 no

Answerthe simplified expression isexplanationthe given expression is,let us deal with the bracket first.the two negatives in the parenthesis will become positive.the expression now becomes,we now expand the parenthesis to get,we group like terms to obtain,this simplifies to,