An object has a constant acceleration of 40 ft/sec2, an initial velocity of −20 ft/sec, and an initial position of 10 ft. find the position function, s(t), describing the motion of the object.
i'm all the way up to here, what do i do now?
a(t)=40 v(0)=-20 s(0)=10
the integral of 40 dt, antiderivative is v(t)=40t+c
40(0)+c=-20
c=-60
s(t)=integral of (40(t)-60)dt
antiderivative is 20t^2-60t+c

The equation that describes the motion of the object is

Step-by-step explanation:

It is given that,

Acceleration of the object at time t is:

Initial velocity or velocity at t = 0,

Initial position or position at t = 0,

Since,

............(1)

At t = 0,

→

Equation (1) becomes :

Since,

............(2)

At t = 0,

→

Equation (2) becomes:

Hence, this is the required solution.

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

john got lost so he didn't know what to do and it was crazy because he didn't except it

step-by-step explanation:

123123 step byt step