Assume that lines that appear to be tangent are tangent. o is the center of the circle. find the value of x. (figures are not drawn to scale.)

The measure of x is 45 degrees

The angle at the tangent (T) of a circle is 90 degrees.

So, we have:

The above angle means that the angles at the two tangents equal 90 degrees.

--- the sum of angles in a quadrilateral

Substitute 90 for T

Subtract 180 from both sides

Given that the angles at both tangents are equal, then:

Substitute 3x for O in

Divide both sides by 4

Hence, the value of x is 45 degrees

Read more about cyclic quadrilaterals at:

link

answer: i guess 5 units?

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15