After 273 m3 of ethylene oxide is formed at 748 kpa and 525 k, the gas is cooled at constant volume to 293 k. the new pressure is

Therefore, the new pressure is 417.455 kPa

Step-by-step explanation:

As per general gas equation

If Volume of a gas is constant then equation is represented by

Here and

If then we have to calculate the value of

Now we plug in the values in the equation

\frac{748}{525}=\frac{P_{2}}{293}

kPa

Therefore, the new pressure is 417.455 kPa

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.

i would need to see the shape

step-by-step explanation: