Searches related to which ordered pair (ab) is a solution to the given system (2a -5b=1, 3a+5b=14

Ordered pair: (3,1)

Step-by-step explanation:

Given: System of equation

2a - 5b = 1  and  3a + 5b = 14

Using elimination method.

In this method, we make same coefficient of any one variable and cancel it.

2a - 5b = 1  

3a + 5b = 14

We make coefficient of a same.

2a - 5b = 1     ( Multiply by 3)

6a - 15b = 3

3a + 5b = 14   (Multiply by -2)

-6a - 10b = -28

Add both equation

6a - 15b = 3

-6a - 10b = -28

     -25b = -25

          b = 1

Put b=1 into 2a - 5b = 1  

2a - 5(1) = 1

        2a = 6

          a = 3

Solution: a=3 and b=1

Ordered pair: (3,1)

Hence, The Ordered pair (3,1) is a solution to the given system of equation.

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

9987

step-by-step explanation: