1. find the perimeter of the triangle with coordinates a (1, 2), b( 6, 5), and c (1, 7)

The perimeter is just the sum of all side lengths.  Here we have sides AB, BC, and AC.

The side lengths are found using the pythagorean theorem...

d^2=(dx)^2+(dy)^2

AB^2=5^2+3^2=34,  AB=√34

BC^2=5^2+2^2=29, BC=√29

AC^2=0^2+5^2=25,  AC=√25

So the perimeter is:

P=√34+√29+√25

P≈16.22 units (to the nearest hundredth of a unit)

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