Immediately i have waited all day and no response so im posting again

Using the form y=a(x-h)²+k

We can look at the vertex (-3,-2) which gives us the values of h,k

h=3, k=-2

Thus y=a(x+3)²-2

Then we can solve for a using any point on the line
- I'll use (-4,-1)

Insert the values of x,y into  y=a(x+3)²-2 
--> x=-4, y=-1

y=a(x+3)²-2
-1=a(-4+3)²-2
-1=a(-1)²-2
a-2=-1
a=-1+2
a=1

Insert the value of a
y=1(x+3)²-2
  = (x+3)²-2

Thus y=(x+3)²-2 is the final equation in standard form