If the sum of three consecutive integers is 99 what is the smallest integer

Three consecutive numbers are n, n+1, and n+2.  We are told that the sum of these is 99 so:

n+n+1+n+2=99

3n+3=99

3n=96

n=32

So the smallest number of the three is 32

check...

32+33+34=99

99=99

If your asking how much altogether for 12 performance the answer will be 98,496.