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![\bf y=8ln[sin(t+9)]\\\\ -----------------------------\\\\ \cfrac{dy}{dx}=8\cdot \cfrac{cos(t+9)\cdot 1}{sin(t+9)}\implies \cfrac{dy}{dx}=8cot(t+9)](/tpl/images/0274/7973/9dcd7.png)
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Find the derivative of y=8ln(sin t+9)...
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