At a carnival, food tickets cost $2 each and ride tickets cost $3 each. a total of $1,240 was collected at the carnival. the number of food tickets sold was 10 less than twice the number of ride tickets sold. the system of equations represents x, the number of food tickets sold, and y, the number of ride tickets sold. 2x + 3y = 1240 x = 2y – 10 how many of each type of ticket were sold? 180 food tickets and 293 ride tickets 180 food tickets and 350 ride tickets 293 food tickets and 180 ride tickets 350 food tickets and 180 ride tickets

350 food tickets and 180 ride tickets are sold

Step-by-step explanation:

Cost of 1 food ticket = $2

Cost of 1 ride ticket = $3

A total of $1,240 was collected at the carnival.

Let  x be the number of food tickets sold

Let y be the number of ride tickets sold.

Given system of equations:

Now we are supposed to find How many of each type of ticket were sold?

Substitute the value of x from 2 in 1

Thus the number of ride tickets sold is 180.

Substitute the vale of y in 2 to obtain the value of x

Thus the number of food tickets sold is 350.

Hence 350 food tickets and 180 ride tickets are sold

So, Option D is correct.

you need more information to answer this question

step-by-step explanation: