In a two digit number the tens digit is twice the one digit .the difference of the ines digit and half the tens digit is 0 an equation created to find the ones place will have

Step-by-step explanation:

Let the two digit number be xy

Then, x is unit number

y is tenth number

Then, for every two digit number,

It is always written as 10x + y

E.g 53 is 10×5 + 3 =53

78 is 7×10 +8 =78 e.t.c

If the tenth number is twice the unit number

I.e y = 2x

Second condition

Difference between units digit (x) and half of then digit (½y) = 0

I.e x - ½y =0

x = ½y

2x= y

y=2x

This is the same as the first condition

Let x= k

And y=2k

k is a natural number k=1,2,3,4

Solving this equation shows that x and y will have infinitely many solution

answer: it's upside down and i can't read it

step-by-step explanation:

so, converting firstly the mixed fractions to improper fractions and then "adding".