What are the solutions to the equation 2x^2 - 2x - 12 = 0?
a. x = -4, x = 3
b. x = -3, x = 4
c. x = -2, x = 3
d. x = -6, x = 2

2(x)^2 - 2(x) - 12 = ?
  
2(x)^2 - 2(x) - 12

(x)^2 - 6 - x

Multiply ↪1 (-6) = -6

1 + -6 = -5 , right?

-3 + 2 = -1, right?

After we have pulled out the like terms we have to add/subtract!   x(x) - 3

Search for the common denominator
2(x) - 3

You can add up 4 for your terms
x + 2 (x - 3)

Make sure you solve this↪ 2 = 0

x + 2 = ?
x + 2 = 0
We have found the first; x = -2

Since, this one has a single variable, I'll make the step easier and quicker

Solve this part ↪    x-3 = 0 
If we had the number 3 to your sides we would have found the outcome of the next x
                    
So, the second x is 3 

So, therefore your answer would have to be x =-2 ; x = 3 (most likely option C.)

The distance from point a to point c across the coordinate plane is aproxamatly 8.94 rounded to the nearest hundredth. you use a^2 + b^2 =c^2