Let g be the function given by g(x)=x^2e^kx, where k is a constant. for what value of k does g have a critical point at x=2/3

K= -3

Step-by-step explanation:

If g(x) be the function given by

where k is a constant.

We have to find the value of k when the function has a critical point at x =

Since g'(x) =

Now for critical point we will find derivative of g(x) and equate the derivative to zero.

g'(x) =

Now for

Sin ≠ 0

therefore,

Therefore, k = -3 is the answer

i think it's b

step-by-step explanation:

because the graph is 2 above (0,0)