For accounting purposes, the value of assets (land, buildings, equipment) in a business are depreciated at a set rate per year. the value, v(t), of $384,000 worth of assets after t years, that depreciate at 16% per year, is given by the formula v(t) = vo(b)t. what is the value of vo and b, and when rounded to the nearest cent, what are the assets valued at after 7 years?

Worth of assets after 7 years will be $113314.70

Step-by-step explanation:

The value V(t) of asset after t years is given by the formula

In the formula given V(t) = Worth of asset after t years

and is the initial value of the assets.

Since rate of depreciation of the assets is = 16% per year

So by the given formula

b = (1 - 0.16)

b = 0.84

Now we have to calculate the value of assets worth $384000 after 7 years.

By the given formula

= 384000(0.295)

= $113314.70

Therefore, worth of assets after 7 years will be $113314.70.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.