Leann says 18÷6=3 so 1.8÷0.6=0.3 and 0.18÷0.06=0.03 is leann correct? explain how to solve these divison problems

Leann is incorrect. All the result for those divisions are the same, which is 3.

Given:

Leann says  18:6 = 3

                    1.8:0.6 = 0.3

                    0.18: 0.06 = 0.03

Question:

Explain how to solve these division problem!

We are going to solve this divide a decimal-by-a decimal problem. When a decimal dividing by a decimal, first, we need to change the decimal numbers into a whole number by multiplying with 10, 100 or 1000 to shifting the decimal place.

Let's solve the problem above!

1.) First division

18:6 = 3 we can write this into a fraction

In this case, this number is already a whole number so we just dividing the number straightly:

2.) Second division

1.8 : 0.6 We can change them into a fraction as follow

Let's change those decimal into a whole number by multiply the denominator and numerator with 10 to shifting the decimal place.

By multiply with it's not change the result, only to make the division process easier.

3) Third division

0.18 : 0.06 write this in a fraction. To shifting the decimal point, we need to multiply both the numerator and denominator with 100, so it makes a whole number.

From the division process above, we get the result for all the three divisions is 3

18:6 = 3

1.8:0.6 = 3

0.18: 0.06 = 3

Additional fraction

Total spend

Decimal multiplication

Decimal multiplication

Keywords: fraction, dividing a decimal-by-a decimal, dividing decimal, division problem

560

step-by-step explanation:

giggidy

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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