the area of a rectangular room is 750 square feet. the width of the room is 5 feet less than the length of the room.
which equations can be used to solve for y, the length of the room? check all that apply.

a) 750 – y(y – 5) = 0

b) y(y + 5) = 750

c) y(y – 5) + 750 = 0

d) (y + 25)(y – 30) = 0

e) y2 – 5y = 750

Worth 100 points need the answers asap first row -x^2 2x^2 (x/2)^2 x^2 x is less than 2 x is greater than 2 x is less than or equal to 2 x is greater than or equal to 2 second row -5 -5/2 4 5 •2 is less than x& x is less than 4 •2 is less than or equal to x & x is less than or equal to 4 •2 is less than or equal to x& x is less than 4 •2 is less than x& x is less than or equal to 4