Solve this problem by using a two order system. a man invests $5,200, part at 4% and the balance at 3%. if his total income for the two investments is $194, how much money did he invest at each rate? $ a0 at 4% and $ a1 at 3%

Let $x be the amount of money that a man invested in 3% account and $y be the amount of money a man invested at 4% account. The problem can be modelled by the system of two equations.

1. The income for the 1st investment is $0.03x and the income for the 2nd investment is $0.04y.

If his total income for the two investments is $194, then

0.03x+0.04y=194.

2. If a man invests $5,200, part at 4% and the balance at 3%, then

x+y=5,200.

3. You get a system of equations:

From the 1st equation express x and substitute it into the 2nd equation:

Then

$1,400 at 3% and $3,800 at 4%.

im alright what do you need

step-by-step explanation:

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."