The dot plot below shows the amount of time two random groups of students took to solve a puzzle:
a dot plot shows puzzle solving time in seconds on the horizontal axis. for group a, there is 1 dot on 65, 1 dot on 67, 1 dot on 77, 1 dot on 79, 1 dot on 88, 1 dot on 90, 2 dots on 92, 1 dot on 100, 2 dots on 102, 1 dot on 109, 1 dot on 110, 2 dots on 112, 1 dot on 122, 1 dot on 136, and 1 dot on 139. for group b, there are 2 dots on 50, 1 dot on 55, 1 dot on 61, 2 dots on 70, 2 dots on 80, 2 dots on 89, 1 dot on 95, 3 dots on 100, 1 dot on 110, and 1 dot on 114.
based on visual inspection of the dot plots, which of the following groups, if any, shows a greater average time required to solve the puzzle?
group a
group b
both groups show about the same average time.
no conclusion about average time can be made from the data.

Based on the dot plot the group that has a greater average time is:

Group A.

Step-by-step explanation:

Clearly from the set of values from the dot plot we have that For Group A the dots are assigned to a higher value ( i.e. the range of the values are between 65 to 139) that means that it will result in more average (or mean) whereas in Group B the values are assigned to a lesser value ( as the range is between 50 to 114) and hence will result in a lower mean.

Also , we may calculate mean for each group as:

Group A:

Similarly for Group B we have:

Hence, Group A has a greater average time.

hello, sorry being so rude after all that fighting i found it kind of funny, so as me saying sorry here is an answer!

since the table showed her that   2km = 2000m.

to determine, how many km in 2000m, she would divide by 1000.

= 2000 / 1000 = 2 km.

similarly, for 8000m = 8000 / 1000 = 8 km

cheers to savings

~

your pal papaguy

kayla would of sent 8

step-by-step explanation: