Write the point-slope form of the line that passes through (6, 1) and is perpendicular to a line with a slope of -3

Hello:
the equation is : y = ax+b
the slope is a : a×(-3) = -1( perpendicular to a line with a slope of -3)
a = 1/3          y=(1/3)x+b
the line that passes through (6, 1) : 1 = (1/3)(6)+b
b = -1
 the equation is :  y  = (1/3)x-1

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

make sure you have version 2.50

try looking in the very back of the book : )

step-by-step explanation:

you can download it here