The area of a rectangle is 56 cm. the length is 2 cm more than x and the width is 5 cm less than twice x. solve for x. round to the nearest whole number.

56=(x+2)x(2x-5)
56=2x^2-5x+4x-10
56=2x^2-x-10
0=2x^2-x-66(use midterm breaking now)
0=2x^2+11x-12x-66
0=2x(x-6)+11(x-6)
So factors are (2x+11) or (x-6) as the length is always positive we chose x-6 so x-6=0..x=6 is the answer thanks now plz select answer as brainliest :)