7-107. identify the terms, coefficients, constant terms, and factors in each expression below.
a. 3x2 + (−4x) + 1
b. 3(2x − 1) + 2

a. Terms:

Coefficients: 3, -4

Constant terms: 1

Factors: (3x -1) and (x -1)

b. Terms: 6x, -1

Coefficients: 6

Constant terms: -1

Factors: No factors

Step-by-step explanation:

The given expressions are:

a.

b. 3(2x -1) + 2

Let's take the first expression

can be written as because +(-4x) = -4x

Terms:

Coefficients: 3, -4

Constant terms: 1

Factors:

=

So, the factors are (3x -1) and (x -1)

Let's take second expression.

3(2x -1) + 2

Let's simplify this. Using the distributive property a(b -c) = ab - ac

3(2x -1) + 2  = 3(2x) +3(-1) + 2

= 6x - 3 + 2

= 6x -1

Terms: 6x, -1

Coefficients: 6

Constant terms: -1

Factors:

No factors

the answer is 8

step-by-step explanation:

3.14 x 8x8

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]