Aparatrooper jumps from a plane at an altitude of 4500 ft and descends at the rate of 20 ft/sec. what is the formula for the paratrooper’s height, h, above the ground after t seconds?

a: h=4500/20t
b: h=20t+4500
c: h=4500+20t
d: h=4500/20*t

Lets test if a paratrooper is descending at a rate of 20 feet per second and he has been in the air for 10 seconds how far away is he from the ground.  20 x 10 = 200 feet.  Now we subtract 200 from 4500 to get 4300.  Which means the equation has to be h = 4500-20 · T and it looks like your answer might be D.  Hope this helped.

Hdbhebdbshshhsiwbsj ishdhjabrht. tiehwoejh utgv ha j. event