Arocket is fired upward from some initial distance above the ground. its height is h, above the ground t seconds after it was fired, is given h=-16t^2+96t+3952. what was the rockets maximum height? how many seconds did it take to reach maximum height? after it is fired, how many seconds does it take to hit the ground?

answer:

c. the third graph

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet