Use the law of sines to solve the following triangle. approximate your answers to the nearest tenths. c = 10.2 in, a = 45.1° b = 75.8°

Law of sines says
a/sinA=b/sinB=c/SinC
where a,b,c are sides of a triangle and A,B,C are angles respectively.
a/sin45.1=c/sin59.1

(we can find angle C by sum of angles of a triangle is 180.)

a=sin(45.1) x 10.2/sin (59.1)

a=0.708 x 10.2/0.85
a=8.496
a=8.5 units

now u can find b and c sides.