Find all solutions of the equation in the interval [0,2pi).
8sec^2x+4tan^2x-12=0...
Mathematics, 04.10.2019 17:50 jermainedwards
Find all solutions of the equation in the interval [0,2pi).
8sec^2x+4tan^2x-12=0
Answers: 1
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Complete the square to determine the minimum or maximum value of the function defined by the expression. x2 − 12x − 2 a) maximum value at 38 b) minimum value at 38 c) maximum value at −38 d) minimum value at −38
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