Solve x2 + 10x + 12 = 36 for x. x = –12 or x = 2 x = –11 or x = 1 x = –2 or x = 12 x = –1 or x = 11

option 1st is correct

x = -12 or x = 2

Step-by-step explanation:

Solve:

Subtract 36 from both sides we have;

Split the middle term we have;

then;

Take x+12 common we have;

By zero product property, if ab =0 then a = 0 or b = 0

then;

x+12 = 0 or x -2 =0

⇒x = -12 or x = 2

therefore, the solutions are x = -12 or x = 2

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4