In δabc shown below, segment de is parallel to segment ac: triangles abc and dbe where de is parallel to ac the following two-column proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally: statement reason 1. line segment de is parallel to line segment ac 1. given 2. line segment ab is a transversal that intersects two parallel lines. 2. conclusion from statement 1. 3. ∠bde ≅ ∠bac 3. corresponding angles postulate 4. 4. 5. 5. 6. bd over ba equals be over bc 6. converse of the side-side-side similarity theorem which statement and reason accurately completes the proof? 4. δbde ~ δbac; side-angle-side (sas) similarity postulate 5. ∠b ≅ ∠b; reflexive property of equality 4. ∠b ≅ ∠b; reflexive property of equality 5. δbde ~ δbac; angle-angle (aa) similarity postulate 4. δbde ~ δbac; side-angle-side (sas) similarity postulate 5. ∠a ≅ ∠c; isosceles triangle theorem 4. ∠a ≅ ∠c; isosceles triangle theorem 5. δbde ~ δbac; angle-angle (aa) similarity postulate