Let f(x) = x^2-16x+71. what is the vertex and minimum value of f(x)?
2 answers to this (meaning two letters)
a) vertex is (-8,7)
b) vertex is (8,7)
c) vertex is (7,-8)
d) minimum value is 7
e) minimum value is 71
f) minimum value is 8

The veretx is normally the minimum value
hack:
for f(x)=ax²+bx+c
the x value of the vertex is -b/2a
so
f(x)=1x²-16x+71
x value is -(-16)/(2*1)=16/2=8
find f(8) to find y value of vertex

f(8)=8²-16(8)+71
f(8)=64-128+71
f(8)=7

the vertex is (8,7)
the minimum value is 7