Triangle abc is translated according to the rule (x, y) → (x + 2, y – 8). if the coordinates of the pre-image of point b are (4, –5), what are the coordinates of b'? (2, 3) (1, –9) (–3, –4) (6, –13)

the coordinates of B' is (6,-13)

Step-by-step explanation:

Triangle ABC is translated according to the rule (x, y) → (x + 2, y – 8).

Given :Coordinates of the pre-image of point B are (4, –5)

Apply the translated rule to get the coordinates of B'

rule (x, y) → (x + 2, y – 8)

Add 2 with x  and -8 with y to get the new coordinates

Point (4,-5) -> (4+2, -5-8) -> (6,-13)

So the coordinates of B' is (6,-13)

the coordinates of B' is (6,-13)

Step-by-step explanation:

Triangle ABC is translated according to the rule (x, y) → (x + 2, y – 8).

Given :Coordinates of the pre-image of point B are (4, –5)

Apply the translated rule to get the coordinates of B'

rule (x, y) → (x + 2, y – 8)

Add 2 with x  and -8 with y to get the new coordinates

Point (4,-5) -> (4+2, -5-8) -> (6,-13)

So the coordinates of B' is (6,-13)

where's the diagrams?

i dony know

step-by-step explanation: