The graph of which function will have a maximum and a y-intercept of 4?
a. f(x) = 4x2 + 6x – 1
b. f(x) = –4x2 + 8x + 5
c. f(x) = –x2 + 2x + 4
d. f(x) = x2 + 4x – 4

The quadratic equation have the coefficient of less than zero therefore its graph has a maximum point and it also have y-intercept equal to 4.

The quadratic equation that have the coefficient of less than zero, then the graph of that quadratic equation have a maximum point.

Therefore according to the given equation the quadratic equation that have a maximum point are: .

Now, to evaluate the value of y-intercept, put the value of x equal to zero.

a).

put x = 0 in above equation to get the y-intercept:

So, the equation   has y-intercept -1.

b).

put x = 0 in above equation to get the y-intercept:

So, the equation   has y-intercept 5.

c).

put x = 0 in above equation to get the y-intercept:

So, the equation    has y-intercept 4.

d).

put x = 0 in above equation to get the y-intercept:

So, the equation   has y-intercept -4.

Therefore, the correct option is c).

For more information, refer the link given below:

link

answer: do we write it

step-by-step explanation:

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph