Can y'all on 39 and 40 and plz explain

I only know 40
there are 7 spaces and there are 4 odd and three even spaces.
it is asking what is the probably of not landing on an odd.
there are 4 odds and the rest are even.
so the it is 3 spaces out of 7

it is J 3 over 7

I am not sure the answer for 39 but #40 is J

The question is asking you what fraction of the spinner show the arrow that will NOT land of odd #s. the circle is cut into 7, there is only 3 #s that are not odd. 7 is the denominator and 3 is the numerator

I am sorry that my explaination might confuse you
Hope this help:) :P

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.