How many, and what type of, solutions does 6x^2 - 2x + 7 = 0 have?

1 rational solution
2 no real solutions
2 rational solutions
2 irrational solutions

Yo need to use discriminant

for ax²+bx+c=0
the discriminat is b²-4ac

if the discriminant is
1. less than 0, then 0 real solutions
2. equal to 0, then 1 real solutions
3. if more than 0, then 2 real solutions

given

6x²-2x+7=0
a=6
b=-2
c=7
(-2)²-4(6)(7)
4-168
we can see this is less than 0
no real solutions