Hikers spent the following amounts of time (in minutes) to complete a nature hike: 48, 46, 52, 57, 58, 52, 61, 56.
a. find the mean and median times:
b. does one measure describe the data better than the other? explain.
c. suppose another hiker takes 92 minutes to complete the hike. find the mean and median times including the new times.
d. does one measure describe the data better than the other now? explain.

Step-by-step explanation:

Given that hikers spent the following amounts of time (in minutes) to complete a nature hike:48, 46, 52, 57, 58, 52, 61, 56.

Mean = sum/no of items =

In ascending order this becomes

46, 48, 52, 52, 56, 57, 58, 61

Median is average of middle items

=

Here mean is less than median this implies there are more entries above the mean.  i.e. skewed not symmetrical. For symmetrical distributions mean and median would be equal

c) If 92 is added to this data entry median becomes 56 but mean becomes

while median increases by 4.75

d) Median is better because it is not affected by outliers i.e. extreme values added to the set

the graph in the attached figure

step-by-step explanation:

we have

using a graphing tool

the graph in the attached figure

the roots are ( x-intercepts) x=-0.5,x=1,x=3

the y-intercept is the point (0,3)

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a