Mathematics, 30.09.2019 01:50 pepehammu

Solve using substitution. (c& d)
2c+3d=1
-3c+d=15

Answers: 2

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Answers

Equation 2
-3c+d=15
d=15+3c

Substitute into eq 1
2c+3(15+3c)=1
2c+45+9c=1
11c=-44
c=-44/11

c=-4

Sub into eq 1

2(-4)+3d=1
-8+3d=1
3d=9
d=9/3

d=3

Verify:
2(-4)+3(3)=1
-8+9=1
1=1 -- True.

Answer from: Boayerik

2c + 3d = 1 ⇒ 2c + 3d = 1 ⇒ 2c + 3d = 1
-3c + d = 15 ⇒ 3(-3c + d) = 15 ⇒ -9c + 3d = 15
   -7c = 16
   -7c = 16
   -7 - 7
   c = -2 2/7
   2(2 2/7) + 3d = 1
       4 4/7 + 3d = 1
      -4 4/7    -4 4/7
   3d = -3 4/7
   3d = -3 4/7
      3 3
   d = -1 4/21
   (c, d) = (-2 2/7, -1 4/21)

Answer from: Quest

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

These figures are similar. the perimeter and area of one are given. the perimeter of the other is al

Answer from: Quest

step-by-step explanation:

Multiple choice: select the best answer and click "submit." what is the name of the sides of the t

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Solve using substitution. (c& d)
2c+3d=1
-3c+d=15...

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