There are 3 red marbles 4 white marbles and 1 green marble in a bag. marbles are drawn without replacement. what is the probability that 3 marbles can be dawn without drawing a green marble?
0.625 < my answer>
0.643
0.670
0.998
0.179
did i get it right?

670 because there are 8 total marbles, which means that 7 out of the 8 marbles in the bag are not green.
so, the probability of not drawing a green marble is 7/8.
to draw 3 marbles that aren't green, you multiply 7/8 * 7/8 * 7/8 ,

which = .670. hope that !