The equation for the circle is:
x2+y2−12x+6y−19=0
what is the center of the...
Mathematics, 28.09.2019 13:30 inucornspineapple
The equation for the circle is:
x2+y2−12x+6y−19=0
what is the center of the circle?
a. (-6, 3)
b. (12, -6)
c. (6, -3)
d. (-12, 6)
Answers: 1
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