Arectangle’s length is 5 inches more than twice its width. its area is 50 square inches. which equation can be used to find its width, w? 2w(2w + 5) = 50 2w(w + 5) = 50 w(2w + 5) = 50 w(w + 5) = 50

For this case we define the following variables:

We have that by definition, the area of a rectangle is given by:

Then, we have that the length is 5 inches more than twice its width:

Substituting values we have:

An equation that can be used to find its width, w is:

answer with step-by-step explanation:

a. ∠j is supplementary to ∠k - true:

(opposite angles of a trapezoid are supplementary which means that they add up to 180 degrees)

b. kl is parallel to jm - true:

(opposite sides are parallel to each other in a trapezoid)

c. jk is perpendicular to kl - false:

(clearly, jk does not make a right angle with kl)

d. jk is parallel to lm - false:

(jk and lm are two lines opposite in direction to each other so they cannot be parallel)

e. ∠j is congruent to ∠m - true:

(the angles on each side of the base are congruent)

f. ∠j is congruent to ∠k - false:

(the angles on the same side but opposite side of the base are not congruent)

what "following statement"?

step-by-step explanation: