Factor completely:
4x^2 − 16x^4 + 10x^5
question options:

2x^2(−2 + 8x^2 −5x^3)
2x^2(2x − 8x^2 +5x^3)
2x^2(2 − 8x^2 + 5x^3)
2x(2x − 8x^3 + 5x^4)

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

answer: rolling a number cube and flipping a coin.

step-by-step explanation: