bryce is solving this problem.

264x410 < (do not solve this problem)

what are the partial products bryce will need to solve the problem?

a.
2,640 and 10,560

b.
264 and 1,056

c.
2,640 and 105,600

d.
264 and 2,640 and 10,560

If Bryce does the arithmetic in the way usually taught, his partial products will be
.. 410 * 264 = 0*264 +10*264 +400*264
.. = 0 +2640 +105,600 . . . . . . . . . . . . . . . . . matches selection C


Bryce could do the math using Vedic methods to get
.. 80,000 + (24+2)*1000 +(2*0 +6*1 +4*4)*100 +(6*0+4*1)*10
.. = 80,000 +26,000 +2,200 +40
.. = 108240