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Mathematics, 29.01.2020 09:49 jrstrom9090

Factor completely 3a4y3 βˆ’ 12a3y2 + 6a2y.
3(a4y3 βˆ’ 4a3y2 + 2a2y)
3a2y(a2y2 βˆ’ 4ay + 2)
3y(a4y2 βˆ’ 4a3y + 2a2)
prime

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Factor completely 3a4y3 βˆ’ 12a3y2 + 6a2y.
3(a4y3 βˆ’ 4a3y2 + 2a2y)
3a2y(a2y2 βˆ’ 4ay + 2) <...
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