There are 6 red marbles, 4 blue marbles, and 6 yellow marbles in a bag.

two marbles are chosen without replacing them in the bag.

what is the probability that a red marble is chosen, followed by a blue marble?

enter your answer as a fraction in simplest form, using the / symbol, like this: 42/53

1/24

Step-by-step explanation:

Basically all you gotta do is 1/6 to represent the red marbles and you are only picking up one which is what that 1 represents in the numerator. Then, you have 1/4 to represent the one out of the blue marbles. You then multiply those two answers together to get 1/24.

y - y1 = m(x- x1)

y - (-5) = 2/3(x -0)

y + 5 = 2/3x

y = 2/3x - 5