Mathematics, 18.09.2019 22:30 justaguy15

What are the mean, median, and mode of {6,8,4,8,8,5}

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Answer from: mykiagamble

$\huge\text{Hey there!}$

The word mean in mathematics is the average number. So, when you hear or see a question asking what is the mean... just think it’s asking “what is your average number”To find your mean you have to $\downarrow$ Add all of your numbers in your given in the data plot Then, you have to divide your total from addition equation by the total numbers you have in your data set The formula is: $\mathsf{\mu= \dfrac{\sum x}{n}}$ The word median in mathematics is the middle number. So, when you hear or see a question what is the median... just think it’s asking “what is number in the middle?” To find your median you have to $\downarrow$ Put your numbers in your data plot from least to greatest The formula is: $\mathsf{\dfrac{n + 1}{2}}$ The word mode in mathematics is the number you see more than once. So, when you hear or see a question asking what is your mode... just think of it asking “what number is being repeated in your data plot?” To find your mode you have to $\downarrow$ You have to go through your data plot and look for the data plot and look for number you see more than onceThe formula is: $\mathsf{MODE = L + H\ \dfrac{f_m + f_1}{f_m-f_1+f_m + f_2}}$

Okay now lets answer your question

$\large\text{Looking for your \bf mean}\downarrow\\\\\mathsf{\dfrac{6+8+4+8+8+5}{6}}\\\\\mathsf{6+8+4+8+8+5}\\\mathsf{= 14+4+8+8+5}\\\mathsf{= 18 + 8 + 8+5}\\\mathsf{= 26 + 8+5}\\\mathsf{= 34 + 5}\\\mathsf{= \bf 39}\\\\\mathsf{= \dfrac{39}{6}}\\\\\mathsf{= \bf 6.5}\\\\\boxed{\huge\text{Therefore, your MEAN is: \bf 6.5}}\huge\checkmark$

$\large\text{Looking for your \bf median}\downarrow\\\\\mathsf{6,8,4,8,8,\& 5}\\\mathsf{= 4,5,6, 8,8,8}\\\\\large\text{There is NO number that is equal on both sides so this means }\\\large\text{that you do not have a number in the data set that could be your}\\\large\text{median. A number between 6 \& 8 is \bf 7}\large\text{ so 7 could possibly be your}\\\large\text{median}\\\\\boxed{\huge\text{Therefore your MEDIAN is: \bf 7}}\huge\checkmark$

$\large\text{Looking for your \bf mode}\downarrow\\\\\large\text{6, 8, 4, 8, 8, \& 5}\\\\\large\text{6 appeared ONE TIME}\\\large\text{8 appeared THREE TIMES}\\\large\text{4 appeared ONE TIME}\\\large\text{5 appeared ONE TIME}\\\\\large\text{So, the number that you seen/see more than once is: \bf 8}\\\\\boxed{\huge\text{Therefore, your MODE is: \bf 8}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

Answer from: Quest

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

Answer from: Quest

ljn

step-by-step explanation: