Suppose the population of a town is 100,000 in 1999. the population increases at a rate of 4.5% every year. what will be the population of the town in 2005? round your answer to the nearest whole number.

130,226.

Step-by-step explanation:

We have been given that the population of a town is 100,000 in 1999. The population increases at a rate of 4.5% every year.

We will use exponential growth function to solve our given problem. We know that exponential function is in form , where,

= Final value,

a = Initial value,

b = For growth b is in form , where r represents rate in decimal form.  

Let us convert 4.5% into decimal form.

Upon substituting our given values in exponential growth formula, we will get:

, where x represents number of years after 1999.

To find population of town in 2005, we will substitute (2005-1999=6) in our function.

Therefore, the population of the town in 2005 will be 130,226.

idk

step-by-step explanation:

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