What are the roots of the polynomial equation x3-7x=6x-12?

Take half of the x-term coefficient and square it. Add this value to both sides. In this example we have:

The x-term coefficient = −1

The half of the x-term coefficient = −1/2

After squaring we have (−1/2)2=1/4

When we add 1/4 to both sides we have:

x2−x+1/4=12+1/4

STEP 3: Simplify right side

STEP 4: Write the perfect square on the left.

STEP 5: Take the square root of both sides.

STEP 6: Solve for x.

x=1/2±√49/4

that is,

x1=−3

x2=4

and the one from before 

x=-1

ok thats very interesting

answer: b

step-by-step explanation: