The equation of a linear function in point-slope form is y – y1 = m(x – x1). harold correctly wrote the equation y = 3(x – 7) using a point and the slope. which point did harold use?

when harold wrote his equation, the point he used was (7, 3).
when harold wrote his equation, the point he used was (0, 7).
when harold wrote his equation, the point he used was (7, 0).
when harold wrote his equation, the point he used was (3, 7).

"When Harold wrote his equation, the point he used was (7, 0)"

Option C is correct.

Step-by-step explanation:

Given: Harold correctly wrote the equation y = 3(x – 7) using a point and the slope.

The equation of a linear function in point-slope form is

We will compare the Harold equation with point-slope form

If we compare the equation we get

Harold use the point (7,0) and slope 3.

Hence, The correct option is C. "When Harold wrote his equation, the point he used was (7, 0)"

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

yes because they have the same amount of green and blur marbles.

step-by-step explanation: